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- 1.6
- date 89.07.06.12.50.04; author adam; state Exp;
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- @checked in with -k by kupfer at 92.05.18.17.32.34.
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- text
- @/*-
- * listConcat.c --
- * Function to concatentate two lists.
- *
- * Copyright (c) 1988 by the Regents of the University of California
- *
- * Permission to use, copy, modify, and distribute this
- * software and its documentation for any purpose and without
- * fee is hereby granted, provided that the above copyright
- * notice appears in all copies. Neither the University of California nor
- * Adam de Boor makes any representations about the suitability of this
- * software for any purpose. It is provided "as is" without
- * express or implied warranty.
- *
- */
- #ifndef lint
- static char *rcsid =
- "$Id: lstConcat.c,v 1.6 89/07/06 12:50:04 adam Exp $ SPRITE (Berkeley)";
- #endif lint
-
- #include "lstInt.h"
-
- /*-
- *-----------------------------------------------------------------------
- * Lst_Concat --
- * Concatenate two lists. New elements are created to hold the data
- * elements, if specified, but the elements themselves are not copied.
- * If the elements should be duplicated to avoid confusion with another
- * list, the Lst_Duplicate function should be called first.
- * If LST_CONCLINK is specified, the second list is destroyed since
- * its pointers have been corrupted and the list is no longer useable.
- *
- * Results:
- * SUCCESS if all went well. FAILURE otherwise.
- *
- * Side Effects:
- * New elements are created and appended the the first list.
- *-----------------------------------------------------------------------
- */
- ReturnStatus
- Lst_Concat (l1, l2, flags)
- Lst l1; /* The list to which l2 is to be appended */
- Lst l2; /* The list to append to l1 */
- int flags; /* LST_CONCNEW if LstNode's should be duplicated
- * LST_CONCLINK if should just be relinked */
- {
- register ListNode ln; /* original LstNode */
- register ListNode nln; /* new LstNode */
- register ListNode last; /* the last element in the list. Keeps
- * bookkeeping until the end */
- register List list1 = (List)l1;
- register List list2 = (List)l2;
-
- if (!LstValid (l1) || !LstValid (l2)) {
- return (FAILURE);
- }
-
- if (flags == LST_CONCLINK) {
- if (list2->firstPtr != NilListNode) {
- /*
- * We set the nextPtr of the
- * last element of list two to be NIL to make the loop easier and
- * so we don't need an extra case should the first list turn
- * out to be non-circular -- the final element will already point
- * to NIL space and the first element will be untouched if it
- * existed before and will also point to NIL space if it didn't.
- */
- list2->lastPtr->nextPtr = NilListNode;
- /*
- * So long as the second list isn't empty, we just link the
- * first element of the second list to the last element of the
- * first list. If the first list isn't empty, we then link the
- * last element of the list to the first element of the second list
- * The last element of the second list, if it exists, then becomes
- * the last element of the first list.
- */
- list2->firstPtr->prevPtr = list1->lastPtr;
- if (list1->lastPtr != NilListNode) {
- list1->lastPtr->nextPtr = list2->firstPtr;
- }
- list1->lastPtr = list2->lastPtr;
- }
- if (list1->isCirc && list1->firstPtr != NilListNode) {
- /*
- * If the first list is supposed to be circular and it is (now)
- * non-empty, we must make sure it's circular by linking the
- * first element to the last and vice versa
- */
- list1->firstPtr->prevPtr = list1->lastPtr;
- list1->lastPtr->nextPtr = list1->firstPtr;
- }
- free ((Address)l2);
- } else if (list2->firstPtr != NilListNode) {
- /*
- * We set the nextPtr of the last element of list 2 to be nil to make
- * the loop less difficult. The loop simply goes through the entire
- * second list creating new LstNodes and filling in the nextPtr, and
- * prevPtr to fit into l1 and its datum field from the
- * datum field of the corresponding element in l2. The 'last' node
- * follows the last of the new nodes along until the entire l2 has
- * been appended. Only then does the bookkeeping catch up with the
- * changes. During the first iteration of the loop, if 'last' is nil,
- * the first list must have been empty so the newly-created node is
- * made the first node of the list.
- */
- list2->lastPtr->nextPtr = NilListNode;
- for (last = list1->lastPtr, ln = list2->firstPtr;
- ln != NilListNode;
- ln = ln->nextPtr)
- {
- PAlloc (nln, ListNode);
- nln->datum = ln->datum;
- if (last != NilListNode) {
- last->nextPtr = nln;
- } else {
- list1->firstPtr = nln;
- }
- nln->prevPtr = last;
- nln->flags = nln->useCount = 0;
- last = nln;
- }
-
- /*
- * Finish bookkeeping. The last new element becomes the last element
- * of list one.
- */
- list1->lastPtr = last;
-
- /*
- * The circularity of both list one and list two must be corrected
- * for -- list one because of the new nodes added to it; list two
- * because of the alteration of list2->lastPtr's nextPtr to ease the
- * above for loop.
- */
- if (list1->isCirc) {
- list1->lastPtr->nextPtr = list1->firstPtr;
- list1->firstPtr->prevPtr = list1->lastPtr;
- } else {
- last->nextPtr = NilListNode;
- }
-
- if (list2->isCirc) {
- list2->lastPtr->nextPtr = list2->firstPtr;
- }
- }
-
- return (SUCCESS);
- }
-
- @
-